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6x^2-0.2x-0.48=0
a = 6; b = -0.2; c = -0.48;
Δ = b2-4ac
Δ = -0.22-4·6·(-0.48)
Δ = 11.56
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.2)-\sqrt{11.56}}{2*6}=\frac{0.2-\sqrt{11.56}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.2)+\sqrt{11.56}}{2*6}=\frac{0.2+\sqrt{11.56}}{12} $
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